Penulis Topik: SUBROUTINE 8 bit x 16 bit = 32 bit (Dibaca 5113 kali)

Iman Fushshilat · « **pada:** Januari 09, 2011, 01:24:36 AM »

permisi, mau minta tolong.
Barang kali ada yang punya subroutin perkalian 8 bit dengan 16 bit yang

mana hasil lebar data maksimalnya mampu 32 bit (8 bit x 16 bit = 32

bit)
saya udah coba nyari2 di internet dan menemukan beberapa cuma hasilnya

kurang memuaskan (tidak benar) .
contoh ini:
;====================================================================
; subroutine MUL816
; 8-Bit x 16-Bit to 32-Bit Product signed Multiply
; 2's Complement format
;
; input: r0 = multiplicand X
; r3, r2 = multiplier Y
;
; output: r3, r2, r1, r0 = product P = X x Y (r3 = sign extension)
;
; calls: Cr0, Cr2r3, Mr0r3
;
; alters: acc, C, Bits SignX & SignY
;====================================================================

MUL816: push b
anl PSW, #0E7H ; Register Bank 0
acall Cr0 ; 2's comp -> Mag/Sign
acall Cr2r3 ; 2's comp -> Mag/Sign
mov a, r0 ; load X low byte into acc
mov b, r2 ; load Y low byte into B
mul ab ; multiply
push acc ; stack result low byte
push b ; stack result high byte
mov a, r0 ; load X into acc again
mov b, r3 ; load Y high byte into B
mul ab ; multiply
pop 00H ; recall X*YL high byte
add a, r0 ; add X*YL high and X*YH low
mov r1, a ; save result
clr a ; clear accumulator
addc a, b ; a = b + carry flag
mov r2, a ; save result
pop 00H ; get low result
mov r3, #0
acall Mr0r3 ; Mag/Sign -> 2's Comp
pop b
ret
;=================================================================
; subroutine Cr0
; 8-Bit 2's Complement -> magnitude / Sign Bit Conversion
;
; input: r0 = signed byte
;
; output: r0 = magnitude
; Bit 21H = sign (21H is set if r0 is a negative number)
;
; alters: acc
;=================================================================

Cr0: mov a, r0 ; read X into accumulator
jb acc.7, Cr0a ; X is negative if bit 7 is 1
clr SignX ; clear sign bit if 'positive'
ret ; done

Cr0a: cpl a ; X negative, find abs value
inc a ; XA = complement(XT)+1
mov r0, a ; save magnitude
setb SignX ; set sign bit if 'negative'
ret
;====================================================================
; subroutine Cr2r3
; 16-Bit 2's Complement -> magnitude / Sign Bit Conversion
;
; input: r3, r2 = signed word
;
; output: r3, r2 = magnitude
; Bit 22H = sign (22H is set if negative number)
;
; alters: acc, C
;====================================================================

Cr2r3: mov a, r3 ; read high into accumulator
jb acc.7, c1a ; negative if bit 7 is 1
clr SignY ; clear sign bit if 'positive'
ret ; done

c1a: setb SignY ; set sign flag
mov a, r2 ; number is negative
cpl a ; complement
add a, #1 ; and add +1
mov r2, a
mov a, r3 ; get next byte
cpl a ; complement
addc a, #0
mov r3, a
ret
;====================================================================
; subroutine Mr0r3
; 32-Bit magnitude / Sign Bit -> 2's Complement Conversion
;
; input: r3, r2, r1, r0 = magnitude
; Bits 21H & 22H = sign bits of operands X and Y
; (set if negative)
;
; output: r3, r2, r1, r0 = signed word
;
; alters: acc, C
;====================================================================

Mr0r3: jb SignX, Mr0r3b ; test X sign
jb SignY, Mr0r3a ; test Y sign
ret

Mr0r3b: jnb SignY, Mr0r3a
ret

Mr0r3a: mov a, r0 ; negate number
cpl a ; complement
add a, #1 ; and add +1
mov r0, a
mov a, r1 ; get next byte
cpl a ; complement
addc a, #0
mov r1, a
mov a, r2 ; get next byte
cpl a ; complement
addc a, #0
mov r2, a
mov a, r3 ; get next byte
cpl a ; complement
addc a, #0
mov r3, a
ret ; done

nah ini revisi yang agak baru dari sang penulis program (W.G.Marshall)

tapi tetep masih belum benar juga.

;====================================================================
; subroutine MUL816
; 8-Bit x 16-Bit to 32-Bit Product signed Multiply
; 2's Complement format
;
; input: r0 = multiplicand X
; r3, r2 = multiplier Y
;
; output: r3, r2, r1, r0 = product P = X x Y (r3 = sign extension)
;
; calls: Cr0, Cr2r3, Mr0r3
;
; alters: acc, C, r4, Bits SignX & SignY
;====================================================================

MUL816: push b
acall Cr0 ; 2's comp -> Mag/Sign
acall Cr2r3 ; 2's comp -> Mag/Sign
mov a, r0 ; load X into acc
mov b, r2 ; load Y low into B
mul ab ; multiply
xch a, r0 ; save X*YL low, reload X
mov r4, b ; temp save X*YL high
mov b, r3 ; load Y high into B
mul ab ; multiply
add a, r4 ; add X*YL high and X*YH low
mov r1, a ; save result
clr a
addc a, b ; X*YH high + 0 + carry flag
mov r2, a ; save result
mov r3, #0 ; MS result = 0
acall Mr0r3 ; Mag/Sign -> 2's Comp
pop b
ret

;=================================================================
; subroutine Cr0
; 8-Bit 2's Complement -> magnitude / Sign Bit Conversion
;
; input: r0 = signed byte
;
; output: r0 = magnitude
; Bit SignX = sign (SignX is set if r0 is a negative number)
;
; alters:
;=================================================================

Cr0: xch a, r0 ; read X into accumulator
clr SignX ; clear sign flag
jnb acc.7, Cr0a ; X is negative if bit 7 is 1
cpl a ; X negative, find abs value
inc a ; X = complement(X)+1
setb SignX ; set sign flag
Cr0a: xch a, r0 ; save magnitude
ret
;====================================================================
; subroutine Cr2r3
; 16-Bit 2's Complement -> magnitude / Sign Bit Conversion
;
; input: r3, r2 = signed word
;
; output: r3, r2 = magnitude
; Bit SignY = sign (SignY is set if negative number)
;
; alters: acc, C
;====================================================================

Cr2r3: mov a, r3
clr SignY ; clear sign flag
jnb acc.7, C1a ; high byte negative?
setb SignY ; set sign flag
xch a, r2 ; number is negative
cpl a ; complement
add a, #1 ; and add +1
xch a, r2 ; get MS byte
cpl a ; complement
addc a, #0
mov r3, a
C1a: ret
;====================================================================
; subroutine Mr0r3
; 32-Bit magnitude / Sign Bit -> 2's Complement Conversion
;
; input: r3, r2, r1, r0 = magnitude
; Bits SignX & SignY = sign bits of operands X and Y
; (set if negative)
;
; output: r3, r2, r1, r0 = signed word
;
; alters: acc, C
;====================================================================

Mr0r3: jb SignX, Mr0r3b ; test X sign
jb SignY, Mr0r3a ; test Y sign
ret

Mr0r3b: jnb SignY, Mr0r3a
ret

Mr0r3a: mov a, r0 ; negate number
cpl a ; complement
add a, #1 ; and add +1
mov r0, a
mov a, r1 ; get next byte
cpl a ; complement
addc a, #0
mov r1, a
mov a, r2 ; get next byte
cpl a ; complement
addc a, #0
mov r2, a
mov a, r3 ; get next byte
cpl a ; complement
addc a, #0
mov r3, a
ret ; done

terima kasih

Salam

lutfi · « **Jawab #1 pada:** Januari 09, 2011, 01:43:00 AM »

lieur.......ane bantu sundul atas permintaan yg bikin topik

sundul sundul

Iman Fushshilat · « **Jawab #2 pada:** Januari 09, 2011, 01:51:09 AM »

Kutip dari: lutfi pada Januari 09, 2011, 01:43:00 AM

lieur.......ane bantu sundul atas permintaan yg bikin topik

sundul sundul

nuhun :-)

Iman Fushshilat · « **Jawab #3 pada:** Januari 09, 2011, 10:00:13 AM »

para pakar bantuin donk.....om dian,om risam,om juhar, mas herlambang, om busan...& boss ganteng

purwanto-amm · « **Jawab #4 pada:** Januari 09, 2011, 10:50:36 AM »

wah sy gagerti asembler, biasanya saya ngeprogram mikrokontroler pake Mikro-C yg lebih mudah $:-\$ $:-\$

Iman Fushshilat · « **Jawab #5 pada:** Januari 09, 2011, 11:34:39 AM »

Kutip dari: purwanto-amm pada Januari 09, 2011, 10:50:36 AM

wah sy gagerti asembler, biasanya saya ngeprogram mikrokontroler pake Mikro-C yg lebih mudah $:-\$ $:-\$

wah...sayang sekali
saya malah nga ngerti bahasa C, saya ngerti nya cuma Assambler Doang itu pun cuma buat MCS-51 ( maklum pemula banget)
Terim kasih mas purwanto

Iman Fushshilat · « **Jawab #6 pada:** Januari 17, 2011, 09:01:24 PM »

Waduh.. kemana nih para pakar? corong1

M Joe · « **Jawab #7 pada:** Maret 23, 2011, 01:11:54 AM »

Lho taunya klo gak bener di uji bagaimana..... aku pernah punya... ide1 coba saya cari lagi cari1 sabar ya.... sambil saya coba dulu. kalkulasi1 entar kalo udah saya coba post di sini. Kalo bisa pakai program C emang lebih gampang sih....

purwanto-amm · « **Jawab #8 pada:** Maret 23, 2011, 06:42:14 AM »

Kutip dari: Iman Fushshilat pada Januari 17, 2011, 09:01:24 PM

Waduh.. kemana nih para pakar? corong1

kalo di microC/microBasic/microPascal ada yg namanya data type ato jenis variabel mulai yg size nya kecil 1bit sampe 32bit

Kode: [Pilih]

bit 		1–bit 	0 or 1 
sbit 		1–bit 	0 or 1 
byte,char 	8–bit 	0 .. 255 
short 		8–bit 	-127 .. 128 
word 		16–bit 	0 .. 65535 
integer 	16–bit 	-32768 .. 32767 
longword 	32–bit 	0 .. 4294967295 
longint 	32–bit 	-2147483648 .. 2147483647 
float 		32–bit 	±1.17549435082 * 10-38 .. ±6.80564774407 * 1038

jadi variabel-variabel tersebut bisa lagsung di +, -, * dan /, tanpa harus ada subroutin.... khusus

M Joe · « **Jawab #9 pada:** Maret 24, 2011, 01:01:13 AM »

Coba saya jawab ini saya bikin sendiri aja cari-cari ndak ketemu:
sedikit betulkan pertanyaannya ya.... 8 bit x 16 bit hasilnya maximum 24 bit

contohnya kita kalikan aja nilai 8bit terbesar adalah FF dan 16 bit terbesar FFFF
FF x FFFF = FEFF01 nah hasilnya khan 24 bit.....

procedure yg saya bikin ini digunakan mengalikan nilai 16 bit pada DPTR dan nilai 8 BIT pada R0

hasilnya di simpan di R1,R2,R3

jika dptr di isi FFFF
dan r0 di isi FF

maka hasilnya r1=FE
r2=FF
r3=01

mul16x8:
   MOV A,R0
   MOV B,dpl
   MUL AB
   MOV r3,A
   MOV r2,B
   MOV A,R0
   MOV B,dpH
   MUL AB
   ADD A,r2
   MOV r2,A
   MOV A,#0
   ADDC A,B
   MOV r1,A
   ret

Apakah gini yang dimaksud?

Iman Fushshilat · « **Jawab #10 pada:** Maret 24, 2011, 01:20:27 PM »

Kutip dari: purwanto-amm pada Maret 23, 2011, 06:42:14 AM

Kutip dari: Iman Fushshilat pada Januari 17, 2011, 09:01:24 PM
Waduh.. kemana nih para pakar? corong1

kalo di microC/microBasic/microPascal ada yg namanya data type ato jenis variabel mulai yg size nya kecil 1bit sampe 32bit

Kode: [Pilih]
bit 1–bit 0 or 1 sbit 1–bit 0 or 1 byte,char 8–bit 0 .. 255 short 8–bit -127 .. 128 word 16–bit 0 .. 65535 integer 16–bit -32768 .. 32767 longword 32–bit 0 .. 4294967295 longint 32–bit -2147483648 .. 2147483647 float 32–bit ±1.17549435082 * 10-38 .. ±6.80564774407 * 1038

jadi variabel-variabel tersebut bisa lagsung di +, -, * dan /, tanpa harus ada subroutin.... khusus

Wah...enak juga ya, kalo gitu.
Cuma sayangnya saya bisa nya cuma bahasa Assembler doang, itu juga masih belajar, belum mahir

Iman Fushshilat · « **Jawab #11 pada:** Maret 24, 2011, 01:24:14 PM »

Kutip dari: M Joe pada Maret 24, 2011, 01:01:13 AM

Coba saya jawab ini saya bikin sendiri aja cari-cari ndak ketemu:
sedikit betulkan pertanyaannya ya.... 8 bit x 16 bit hasilnya maximum 24 bit

contohnya kita kalikan aja nilai 8bit terbesar adalah FF dan 16 bit terbesar FFFF
FF x FFFF = FEFF01 nah hasilnya khan 24 bit.....

procedure yg saya bikin ini digunakan mengalikan nilai 16 bit pada DPTR dan nilai 8 BIT pada R0

hasilnya di simpan di R1,R2,R3

jika dptr di isi FFFF
dan r0 di isi FF

maka hasilnya r1=FE
r2=FF
r3=01

mul16x8:
   MOV A,R0
   MOV B,dpl
   MUL AB
   MOV r3,A
   MOV r2,B
   MOV A,R0
   MOV B,dpH
   MUL AB
   ADD A,r2
   MOV r2,A
   MOV A,#0
   ADDC A,B
   MOV r1,A
   ret

Apakah gini yang dimaksud?

iya, seperti ini. terima kasih banyak. Mr joe.
Oia , saya nyobanya pake IDE+ simulator buat nulis program MCS-51, nama nya MicroV7.

KOMUNITAS HOBBIYST ELEKTRONIKA - KHE

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Penulis Topik: SUBROUTINE 8 bit x 16 bit = 32 bit (Dibaca 5113 kali)

Iman Fushshilat

SUBROUTINE 8 bit x 16 bit = 32 bit

lutfi

Re:SUBROUTINE 8 bit x 16 bit = 32 bit

Iman Fushshilat

Re:SUBROUTINE 8 bit x 16 bit = 32 bit

Iman Fushshilat

Re:SUBROUTINE 8 bit x 16 bit = 32 bit

purwanto-amm

Re:SUBROUTINE 8 bit x 16 bit = 32 bit

Iman Fushshilat

Re:SUBROUTINE 8 bit x 16 bit = 32 bit

Iman Fushshilat

Re:SUBROUTINE 8 bit x 16 bit = 32 bit

M Joe

Re:SUBROUTINE 8 bit x 16 bit = 32 bit

purwanto-amm

Re:SUBROUTINE 8 bit x 16 bit = 32 bit

M Joe

Re:SUBROUTINE 8 bit x 16 bit = 32 bit

Iman Fushshilat

Re:SUBROUTINE 8 bit x 16 bit = 32 bit

Iman Fushshilat

Re:SUBROUTINE 8 bit x 16 bit = 32 bit